Match a string separated by slashes

Question

In the first sample I want to match Mortal

Input 1:

=Mortal

Regex 1:

=(.+)

Output 1:

MATCH 1
1.  [1-7]   `Mortal`

Works just as I want.

In the second sample, I want to match Mortal and Combat

Input 2:

=Mortal/Combat

Regex 2:

=(.+)\/(.+)

Output 2:

MATCH 1
1.  [1-7]   `Mortal`
2.  [8-14]  `Combat`

Works just as I want.

My problem is that I want a solution that does both.

If I use =(.+)\\/(.+) on =Mortal it matches nothing .

If I use =(.+) on =Mortal/Combat it matches:

MATCH 1
1.  [1-14]  `Mortal/Combat`

Both are incorrect.

Tried to merge them together:

=((.+)\/(.+)|(.+))

Which matches:

MATCH 1
1.  [1-14]  `Mortal/Combat`
2.  [1-7]   `Mortal`
3.  [8-14]  `Combat`

Or:

MATCH 1
1.  [1-7]   `Mortal`
4.  [1-7]   `Mortal`

Definitely incorrect.

Desired output should either be:

MATCH 1
1.  [1-7]   `Mortal`

Or:

MATCH 1
1.  [1-7]   `Mortal`
2.  [8-14]  `Combat`

Would also be cool if it would be compatible with three slashes: =Mortal/Combat/X should become:

MATCH 1
1.  [0-6]   `Mortal`
2.  [7-13]  `Combat`
3.  [14-15] `X`

How can I achieve this?

I am using http://regex101.com to test the regex.

Answer 1

This should work for all the three cases:

^=(.+)\/(.+)\/(.+)|=(.+)\/(.+)|=(.+)$

Explanation:

^                 # Assert position at the beginning of the line
=(.+)\/(.+)\/(.+) # Three slashes
|                 # OR
=(.+)\/(.+)       # Two slashes
|                 # OR
=(.+)             # No slashes
$                 # Assert position at the end of the line

Demo

Answer 2

Live demo

Try this:

=(.*)\/(.*)\/(.*)|=(.*)\/(.*)|=(.*)

Answer 3

=([^\/]+)\/?(.+)?

The ? make it optional. This select everything before / for the first group. The rest are optional

You can change the + with * if you want to match empty values also.

Generic with supporting any amount of /

=(([^\/]+)\/?)*

Just look in group two for the values