SQl Server Average Hours per day

Question

I want to Calculate average hours for week.

eg My Weekly hours are 44:43 (hh:mm) and my Working days are 5 then it should return 8:57

44:43/ 5 ==> 8:57

How i can achieve in SQL Server.

Answer 1

You can convert the time to seconds, then divide, and convert back to time format. Assuming that WeeklyHours are in a time format, something like this:

select dateadd(second, datediff(second, 0, WeeklyHours) / WorkingDays, cast(0 as time))

This expression should definitely work if WeeklyHours is stored as a datetime .

Answer 2

SELECT CONVERT(VARCHAR,CONVERT(INT,DATEPRT(HH,WH))/5)+':'+
        +CONVERT(VARCHAR,(CONVERT(INT,DATEPRT(HH,WH))%5*60+CONVERT(INT,DATEPRT(mm,WH)))/5)
fROM TIME

Answer 3

Here's the query that I have constructed as per your requirements:

DECLARE @TotalHours VARCHAR(5) = '44:43'


SELECT CAST(CAST(AvgMinutes AS INT)/60 AS VARCHAR) + ':'
        + CAST(CAST(AvgMinutes AS INT)%60 AS VARCHAR)
FROM (
        SELECT CEILING((CAST(LEFT(@TotalHours,CHARINDEX(':',@TotalHours) - 1) AS INT ) * 60 
           + CAST(RIGHT(@TotalHours,LEN(@TotalHours) - CHARINDEX(':',@TotalHours)) AS INT ))/5.0) AvgMinutes
     ) AS TotalMinutes

Answer 4

Not getting the calculation. What I am trying to get is (44 + (43 / 60)) / 5. I did 43/60 to convert the mins to hours. As per this requirement, the query comes as

select (cast(SUBSTRING(Data, 1, charindex(':',Data,1) - 1) as int) + 
    (cast(SUBSTRING(Data, charindex(':',Data,1) + 1, len(Data)) as decimal(18,2)) / 60)) / 5
from tblWorkHours