How to split words by strtok function if the spaces are not equal

Question

Suppose I have to split a string into words, (ie "I am Mamun") [here the SPACES ARE NOT EQUAL] I have used 1 space as delimiter in strtok function but got wrong output. Someone please explain this :(

#include <stdio.h>
#include <string.h>

int main ()
{
  char str[] ="# Timestep     No_Moles     No_Specs     CO3 CO2 HO  CHO2    O   CHO3";
  char * pch;
  printf ("Splitting string \"%s\" into tokens:\n",str);
  pch = strtok (str," #");
  while (pch != NULL)
  {
    printf ("%s\n",pch);
    pch = strtok (NULL, " #");
  }
  return 0;
}

my code : http://codepad.org/eRwUDkVh

Answer 1

The problem isn't the different numbers of spaces, it's that the later fields are delimited by a tab not a space. So simply changing

   pch = strtok (NULL, " #");

to

   pch = strtok (NULL, " \t#");
                         ^^

solves the problem.

Answer 2

You have tabs in your string not just spaces. To split properly based on spaces and tabs you should put character \\t into the input of strtok too.

pch = strtok (NULL, " \t#");