I have 4 samples, represented by their means and standard deviations. If I consider a sample size for all of them as 100, how can I perform a one-way ANOVA using the library of rpsychi in R?
The samples are all normal distributed and independent.
These are their values:
S1: mean1=5.5, sd1=0.6
S2: mean2=5.6, sd2=0.5
S3: mean3=5.9, sd3=0.5
S4: mean4=6.1, sd4=0.6
How can I perform subsequently the post-hoc pair wise comparison (Tukey-HSD) using R as well??
I have recently discover a post in other forum with some of my own concerns: http://www.wenda.io/questions/2570717/anova-in-r-using-summary-data.html
It solved partially what I needed. Applying the code published in that web to my data:
mean <- c(5.5,5.6,5.9,6.1)
sd <- c(0.6,0.5,0.5,0.6)
n <- c(100,100,100,100)
q2data.frame <- data.frame(mean,sd,n)
library(rpsychi)
with(q2data.frame, ind.oneway.second(mean,sd,n))
I get the next ANOVA table:
$anova.table
SS df MS F
Between (A) 22.75 3 7.583 24.863
Within 120.78 396 0.305
Total 143.53 399
$omnibus.es
etasq etasq.lower etasq.upper
0.159 0.094 0.219
$raw.contrasts
mean.diff lower upper std
1-2 -0.1 -0.254 0.054 0.078
1-3 -0.4 -0.554 -0.246 0.078
1-4 -0.6 -0.754 -0.446 0.078
2-3 -0.3 -0.454 -0.146 0.078
2-4 -0.5 -0.654 -0.346 0.078
3-4 -0.2 -0.354 -0.046 0.078
$standardized.contrasts
es lower upper std
1-2 -0.181 -0.459 0.097 0.141
1-3 -0.724 -1.002 -0.446 0.141
1-4 -1.086 -1.364 -0.808 0.141
2-3 -0.543 -0.821 -0.265 0.141
2-4 -0.905 -1.183 -0.627 0.141
3-4 -0.362 -0.640 -0.084 0.141
$power
small medium large
0.363 0.993 1.000
Does anybody know how can I get the p-value of the ANOVA analysis? Moreover, how can I perform a TukeyHSD?
Use library(asbio). This will give you t(s), mean differences, upper and lower bounds, HLSD Diff Lower Upper Decision Adj. p-value decision, and adjusted p-value.
#pairwise comparisons
library(asbio)
bonf <- pairw.anova(data$dv, data$group, method="tukey") #also try "bonf" or "lsd"
print(tukey)
#plot(tukey) #can plot the CFs
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