Adding 2 sql values into an array

Question

i am quite new to php and I want to do two select Counts on a mysql column and put these into an array. The code i have is below however this does not work.

// DB connection
  $link = mysqli_connect( "localhost", "username", "password", "CE_TRANSACTIONS" );

// Query users table
  $sql = "SELECT (SELECT COUNT(STATUS) FROM CE_TRANSACTIONS WHERE STATUS = 0),
  (SELECT COUNT(STATUS) FROM CE_TRANSACTIONS WHERE STATUS = 3);"

// Execute query
  $result = mysqli_query($link,$sql);

// Loop over all result rows
  $result_array = array();

     while($array = mysqli_fetch_assoc($result)) 
     {

        $result_array[] = $array[];
     }

// Write to JSON
   echo json_encode($result_array);

Hi thanks for the quick replies i am also getting the following error message PHP Parse error: syntax error, unexpected T_VARIABLE for the below line.

  // Execute query
  $result = mysqli_query($link,$sql);

Answer 1

Change

 $result_array[] = $array[];

to

 $result_array = $array;

You may also see performance boost by using the following query instead.

SELECT Sum(Case When Status = 0 Then 1 Else 0), 
       Sum(Case When Status = 3 Then 1 Else 0)
FROM   CE_TRANSACTIONS

Answer 2

I believe your problem is coming from $array[];

What the [] is saying is 'Access the value at', but you're not accessing any index of the array.

What you want to do is: $result_array[] = $array

Answer 3

The PHP Parse error: syntax error, unexpected T_VARIABLE is because your line

 $sql = "SELECT (SELECT COUNT(STATUS) FROM CE_TRANSACTIONS WHERE STATUS = 0), (SELECT COUNT(STATUS) FROM CE_TRANSACTIONS WHERE STATUS = 3);" 

is missing a trailing ; .