running a python script with values from views.py in Django

Question

I am trying to pass in a value i got in a views.py file in Django into another python script i wrote, but i have no idea how to do so. Here is my code from views.py file:

    def get_alarm_settings(request):
      if request.method == 'POST':
        username = request.POST.get('username')
        password = request.POST.get('password')
        alarm = Alarm.objects.all()[0].alarm_setting
        response = HttpResponse(alarm, content_type='text/plain')
        response_a = execfile('alarm_file.py')
        return response_a

I am trying to pass response into alarm_file.py, does anyone know how to do that?

Answer 1

As per comments under the question, make function in alarm_file.py and import it. To make python alarm_file.py call do the same, use if __name__ == '__main__': an alarm_file.py. It will contain logic to run when called python alarm_file.py . Additionally, you can use sys.argv to get argument, passed in command line. For example:

alarm_file.py:

import sys

def do_something(val):
    # do something
    print val
    # return something
    return val

if __name__ == '__main__':
    try:
        arg = sys.argv[1]
    except IndexError:
        arg = None

    return_val = do_something(arg)

This will ensure that you can run simply: python alarm_file.py some_argument

In your view just import function from alarm_file and use it:

from alarm_file import do_something
...
        response = HttpResponse(alarm, content_type='text/plain')
        response_a = do_something(response)
        return response_a

Answer 2

您可以使用流程响应中间件来处理从view方法返回的响应，有关更多详细信息，请参见https://docs.djangoproject.com/en/dev/topics/http/middleware/#process-response

Answer 3

You cannot pass arguments using execfile(), if you want to call another instance of the interpreter and run the script, you should probably use subprocess.popen ( suprocess docs )

Something like this: subprocess.Popen(['alarm_file.py', 'arg1', ...], ..., shell=True)

Answer 4

I would suggest you to use Popen method of Subprocess module.

For Example:

process = Subprocess.Popen(['python','alarm_file.py','arg1','arg2'], stdout=PIPE, stderr=STDOUT)
output = process.stdout.read()
exitstatus = process.poll()

In this example, stderr and stdout of the script is saved in variable ' output ', And exit code of the script is saved in variable ' exitstatus '.

You can refer my blog for detailed explanation >>

http://www.easyaslinux.com/tutorials/devops/how-to-run-execute-any-script-python-perl-ruby-bash-etc-from-django-views/