Python, counting from an inputted string. Needs to be returned in a specific order?

Question

So i am typing a code where a user will need to input >>Count('bla bla bla') and the program needs to count the in the bla bla bla phrase and return the word with its count in this SPECIFIC order.

Any Help?

Answer 1

Your count function is not used correctly. You want text.search(vowel) , not vowel.search(text)

>>> s = 'this is some string with a lot of vowels'
>>> vowels = 'aeiou'
>>> {i : s.count(i) for i in vowels}
{'a': 1, 'i': 4, 'e': 2, 'u': 0, 'o': 4}

Dictionaries have no order, so if you want the count in vowel order:

>>> [(i,s.count(i)) for i in vowels]
[('a', 1), ('e', 2), ('i', 4), ('o', 4), ('u', 0)]

Answer 2

def vowelCount(text):
    vowels = 'aeiou'
    return ("a, e, i, o, and u appear, respectively, %s times." %", ".join([ str(text.count(x)) for x in vowels]))

print vowelCount('bla bla bla')

Hope this helps.

Answer 3

You made a typo:

def vowelCount(text):
    vowels = 'aeiou'
    counts = {x:text.count(x) for x in vowels}
    keys = counts.keys()
    values = counts.values()
    return ','.join(keys[:-1]) + ' and '+ keys[-1] +' appear, respectively, '+ ','.join(str(v) for v in values)+' times.'

Answer 4

The code as written doesn't even examine the input text at all. You're counting the number of times each vowel appears in vowels .

Replace with text.count(i) instead of vowels.count(i) .