How from dict of list create list of dict

Question

I have dict :

D = {'a': ['1a', '2a', '3a'], 'c': ['1c', '2c', '3c'], 'b': ['1b', '2b', '3b']}

I want to convert D to list of dict :

L = [{'a':'1a', 'b': '1b', 'c': '1c'}, {'a':'2a', 'b': '2b', 'c': '2c'}, ...]

I tried:

>>> l = [(k, v) for k, vals in D.items() for v in vals]
>>> map(dict, zip(*zip(*[iter(l)]*4)))
[{'a': '1a', 'c': '1c', 'b': '1b'}, {'a': '2a', 'c': '2c', 'b': '2b'}, ...

I need more readable solution.

Answer 1

How about this:

L = [dict(zip(D.keys(), vals)) for vals in zip(*D.values())]

Output:

>>> print L
[{'a': '1a', 'c': '1c', 'b': '1b'}, 
 {'a': '2a', 'c': '2c', 'b': '2b'}, 
 {'a': '3a', 'c': '3c', 'b': '3b'}]