find files more than 100 MB from ls -1hl command's output

Question

I'm doing ls -1lh command on certain directories and displaying the output on the GUI.

description of options used in ls command

1 --> print one file/directory in one line
l --> long listing
h --> human readable format (converting in KB, MB, G)

now i have sizes extracted from ls -1lh command:-

size = ["100","9.6K","12M","79M","679M","222K","23","132M","3G","1.3G"]

now i want to find out what sizes are more than 100M in python

What could be my approach? i have to use ls -1lh command because user wants to see the long listing on the directoires

Answer 1

units = dict(K=1024, M=1024*1024, G=1024*1024*1024)
def parse_size(s):
    times = units.get(s[-1:], 1)
    if times == 1:
        return float(s)
    else:
        return float(s[:-1]) * times

Usage:

>>> size = ["100","9.6K","12M","79M","679M","222K","23","132M","3G","1.3G"]
>>> threshold = parse_size('100M')
>>> print [s for s in size if parse_size(s) >= threshold]
['679M', '132M', '3G', '1.3G']

BTW, how about using find if you want to get list of files that is larger than 100MB? find -maxdepth 1 -size +100M