These are my records which i am fetching with this sql , but struggling with finding percentage.
SELECT
(SELECT gender FROM tbl_gender WHERE genderCode = u.genderCode) AS gender,
COUNT(cp.UserID) AS people
FROM tbl_campaign_master cm
INNER JOIN tbl_campaign_played cp ON cp.CampaignCode = cm.campaignCode
INNER JOIN tbl_users u ON cp.UserID = u.userId
WHERE cm.campaignCode = 'CM00000179'
GROUP BY u.genderCode
Gender People
Male 1
Female 1
How to get these results
Gender People Percentage
Male 1 50%
Female 1 50%
I want to know , how we will percentage of each row
based on your output just sample query
declare @t table (gender varchar(10),people int)
insert into @t (gender,people)values('male',1)
insert into @t (gender,people)values('female',1)
Select gender,people, CONVERT(VARCHAR(10),(Count(people)* 100 / (Select Count(*) From @t)))+'%' as Score
From @t
Group By gender,people
you can modify the code in you query as per my assumption
SELECT
(SELECT gender FROM tbl_gender WHERE genderCode = u.genderCode) AS gender,
CONVERT(VARCHAR(10),COUNT(cp.UserID)/(Select Count(*) From tbl_campaign_played WHERE campaignCode = cm.campaignCode ))) AS people
FROM tbl_campaign_master cm
INNER JOIN tbl_campaign_played cp ON cp.CampaignCode = cm.campaignCode
INNER JOIN tbl_users u ON cp.UserID = u.userId
WHERE cm.campaignCode = 'CM00000179'
GROUP BY u.genderCode
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