How do I search for a substring with a variable within a string and replace it with content that contains the substring variable with PHP?
Question
Lets suppose I have a string:
$text = "This is my string exec001 and this is the rest of the string exec222 and here is even more execSOMEWORD a very long string!"
I want to replace each occurrence of "exec?" in the string with some new text and at the same time I want to store the text that follows "exec" in a separate variable so it can be used when replacing the text.
For example, say I want to replace each occurrence of exec??? with, < html>???< /html>< div>???< /div> , so that the resulting string is:
$text2 = "This is my string <html>001</html><div>001</div> and this is the rest of the string <html>222</html><div>222</div> and here is even more <html>SOMEWORD</html><div>SOMEWORD</div> a very long string!"
How can I do this in PHP?
Thanks very much in advance.
2 answers
solution1
1 ACCPTED 2014-08-12 07:18:19
Here is a way to go using preg_replace :
$text = "This is my string exec001 and this is the rest of the string exec222 and here is even more execSOMEWORD a very long string!";
$text2 = preg_replace('/\bexec(\S+)/', "<html>$1</html><div>$1</div>", $text);
echo $text2,"\n";
This will replace all occurrences of execwhatever .
\\S+ stands for any NON space character.
\\b is a word boundary.
You may find more info here .
Output:
This is my string <html>001</html><div>001</div> and this is the rest of the string <html>222</html><div>222</div> and here is even more <html>SOMEWORD</html><div>SOMEWORD</div> a very long string!
Update according to comment
If you want to replace more than one string, just do:
$text2 = preg_replace('/\bexec([^:\s]+):([^:\s]+)/', "<html>$1</html><div>$2</div>", $text);
Where [^:\\s] means any character that is not semi-colon or space
solution2
0 2014-08-12 05:23:34
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