What does the '0x0'. do in this equation $intTotal += '0x0'.$value;

Question

Sorry I am new to php and am getting very confused on a bit of code I am working on.

So I get that intTotal += $value; would just add the value to the intTotal but how does the $intTotal += '0x0'.$value; works? I am getting all sorts of random differences when I chance the 0x0 to something else as well.

Thanks

Answer 1

$value is apparently a string representing a number in hexadecimal.

The string concatenation (the . operator) prefixes it with 0x0 , the 0x prefix is used to denote a hexadecimal number (the extra zero is superfluous).

So for example if $value = "f" , this will produce 0x0f . This will then be converted to the integer 15 by PHP, and added to $intTotal .

Answer 2

0x0只是十六进制表示形式的常规0，与变量语法一起使用时，该类型会转换为字符串'0'

Answer 3

$intTotal += '0x0'.$value; converts $value from hexadecimal number in string to format usable by php and then adds it to $intTotal (after typecasting from string to int).

Edited to add clarity.