I have these two arrays:
array1 = ["a,1", "b,2", "c3", "d4", "e5", "f6"];
array2 = [1, 2, 3, 4];
And I'm trying to find out if an element of the first array is in the second one.
for (i = 0; i < array1.length; i++) {
if(array2.indexOf(array1[i][1]) != -1) {
console.log('In array: '+array1[i][1]);
} else {
console.log('NOT in array: '+array1[i][1]);
}
In this case, I always get the message NOT in array .. .
But if I modify the code this way:
for (i = 0; i < array1.length; i++) {
if(array2.indexOf(1) != -1) {
console.log('In array: '+array1[i][1]);
} else {
console.log('NOT in array: '+array1[i][1]);
}
The output is In array: ... .
With a number as a parameter of the indexOf() function it's working, but no with the variable... how is that possible?
Thank you
In your code:
if(array2.indexOf(array1[i][1]) != -1) {
is comparing a string to a number using strict comparison per the algorithm for indexOf . Also, in most cases you are comparing the wrong character from array1 . In:
"a,1"
character 1 is the comma, not the number. What you need to do is get the numbers from the strings in array1 , convert them to number type so indexOf works using an expression like:
+array1[i].replace(/\D/g,'')
then do the comparison, eg:
array1 = ["a,1", "b,2", "c3", "d4", "e5", "f6"];
array2 = [1, 2, 3, 4];
for (var i=0, iLen=array1.length; i<iLen; i++) {
if (array2.indexOf(+array1[i].replace(/\D/g,'')) != -1) {
console.log('In array: ' + array1[i]);
} else {
console.log('Not in array: ' + array1[i]);
}
}
// In array: a,1
// In array: b,2
// In array: c3
// In array: d4
// Not in array: e5
// Not in array: f6
You may need to modify the regular expression getting the numbers depending on the full range of strings that might be in array1 .
An alternative is to convert the members of array2 to strings and search for them in the members of array1 .
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