G . . PASS VRT=1 GT 0/0 0/0 0/0 0/0 0/0 0/0
G . . PASS VRT=1 GT 0/0 0/0 0/0 0/0 0/0 0/0
C . . PASS VRT=1 GT 0/0 0/0 0/0 0/0 0/0 0/0
I have a file as shown above and i am trying to replace 0/0 with text in column 1.
awk -F'\t' '{ gsub("0/0", $1/$1);}1' OFS="\t" file.txt
The output should look like:
G . . PASS VRT=1 GT G/G G/G G/G G/G G/G G/G
G . . PASS VRT=1 GT G/G G/G G/G G/G G/G G/G
C . . PASS VRT=1 GT C/C C/C C/C C/C C/C C/C
And it throws the error "awk: division by zero". Looks like i am not matching the special characters. Could someone help.
你的意思是 :
awk -F'\t' 'gsub("0/0", $1"/"$1)+1' OFS="\t" file.txt
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