How can I pass an exception that has been thrown in one thread to its calling thread?
I am obliged to use Java version 1.3. Thread.UncaughtExceptionHandler was added in Java 1.5.
I'm quite happy if I have to wrap my code up in a try block and therefore catch the exception inside the thread that caused the exception. My question is how I can pass this exception to the other thread.
Thanks!
Passing an exception to the calling thread can be done with synchronized, wait(), and notify().
class MyThread extends Thread implements Runnable {
public Throwable exception; // a copy of any exceptions are stored here
public void run() {
try {
throw new Exception("This is a test");
}
catch (Throwable e) {
// An exception has been thrown. Ensure we have exclusive access to
// the exception variable
synchronized(this) {
exception = e; // Store the exception
notify(); // Tell the calling thread that exception has been updated
}
return;
}
// No exception has been thrown
synchronized(this) {
// Tell the calling thread that it can stop waiting
notify();
}
}
}
MyThread t = new MyThread();
t.start();
synchronized(t) {
try {
System.out.println("Waiting for thread...");
t.wait();
System.out.println("Finished waiting for thread.");
}
catch (Exception e) {
fail("wait() resulted in an exception");
}
if (t.exception != null) {
throw t.exception;
}
else {
System.out.println("Thread completed without errors");
}
}
try {
System.out.println("Waiting to join thread...");
t.join();
System.out.println("Joined the thread");
}
catch (Exception e) {
System.out.println("Failed to join thread");
}
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