Content of the file is
Feb-01-2014 one two
Mar-02-2001 three four
I'd like to format the first field (the date) to %Y%m%d
format
I'm trying to use a combination of awk and date
command, but somehow this is failing even though i got the feeling i'm almost there:
cat infile | awk -F"\t" '{$1=system("date -d " $1 " +%Y%m%d");print $1"\t"$2"\t"$3}' > test
this prints out date's usage pages which makes me think that the date command is triggered properly, but there is something wrong with the argument, do you see the issue somewhere? i'm not that familiar with awk,
You don't need date
for this, its simply rearranging the date string:
$ awk 'BEGIN{FS=OFS="\t"} {
split($1,t,/-/)
$1 = sprintf("%s%02d%s", t[3], (match("JanFebMarAprMayJunJulAugSepOctNovDec",t[1])+2)/3, t[2])
}1' file
20140201 one two
20010302 three four
You can use:
while read -r a _; do
date -d "$a" '+%Y%m%d'
done < file
20140201
20010302
system() returns the exit code of the command.
Instead:
cat infile | awk -F"\t" '{"date -d " $1 " +%Y%m%d" | getline d;print d"\t"$2"\t"$3}'
$ awk '{var=system("date -d "$1" +%Y%m%d | tr -d \"\\n\"");printf "%s\t%s\t%s\n", var, $2, $3}' file
201402010 one two
200103020 three four
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