regex to match a multi-line string

Question

Sorry, for the badly named topic. I'm looking for a efficient regular expression to match the following:

[2014-11-13 13:05:04] [path/to/class.instagram.php] Options: array (
  'client_id' => '',
  'client_secret' => '',
  'object' => 'tag',
  'object_id' => 'rwar',
  'aspect' => 'media',
  'callback_url' => 'http://www.localthisday.nl/instagram.callback.php',
)

I want it to be split up so it looks like this:

1. [2014-11-13 13:05:04]
2.[path/to/class.instagram.php]
3. Options: array (
  'client_id' => '',
  'client_secret' => '',
  'object' => 'tag',
  'object_id' => 'rwar',
  'aspect' => 'media',
  'callback_url' => 'http://www.localthisday.nl/instagram.callback.php',
)

I'm using this one at the moment:

(\\[(.*)\\])(\\s{1})(\\[(.*)\\])(\\s{1})(.*)/gmi

I know, it's not a very good one, that's probably why it doesn't work the way I want it to work. Problem is; it's a multi-line string, and for some reason it does not work multi-line. Could someone please help me? I'm not that good in regular expressions unfortunately.

Answer 1

Just replace the last (.*) with ([\\S\\s]*) in your regex.

/(\[.*\])\s(\[.*\])\s([\S\s]*)/gmi

DEMO

See the captures at the right side in the above demo link.

Answer 2

使用非贪婪量词：

(\[.*?\])\s(\[.*?\])\s(.*)/gmi

Answer 3

(\]|\))

Try this.Replace by $1\\n .See demo.

http://regex101.com/r/pQ9bV3/32

var re = /(\]|\))/gm;
var str = '[2014-11-13 13:05:04] [path/to/class.instagram.php] Options: array (\n \'client_id\' => \'\',\n \'client_secret\' => \'\',\n \'object\' => \'tag\',\n \'object_id\' => \'rwar\',\n \'aspect\' => \'media\',\n \'callback_url\' => \'http://www.localthisday.nl/instagram.callback.php\',\n)';
var subst = '$1\n';

var result = str.replace(re, subst);