Separating a char from a String?

Question

I am trying to separate the char from the following examples of inputs:

C450.00 C30 P100

I would like to have the char such as "C" or "P" separated so I can work with them alone, as well as the "450.00", "30", and "100" separated as ints. What would be the easiest way to do this?

Answer 1

If the String are always that format:

char ch = yourString.charAt(0);
Double d = Double.valueOf(yourString.substring(1, yourString.length()));

NOTE: I used a Double because you have dots . in the String . You can convert from double to int easily if you won't have any decimals. But that depends on your needings.

Answer 2

You can split the String with whitespace as delimiter. Afterwards use substring on every part of your string. Now you have the C and the 450.0 as Stings. Finally cast the second part of your substring into an integer and you are done.

to split:

String[] parts = string.split(" ");

to substring:

String first = parts[0].substring(0, 1);
String second = parts[0].substring(1);

Answer 3

假设您知道要在给定的String中查找的内容（例如，您知道要查找C字符），则可以使用Regex模式： https : //docs.oracle.com/javase/7/docs/api /java/util/regex/Pattern.html

Answer 4

You can use this library org.​apache.​commons.​lang3.​StringUtils http://commons.apache.org/proper/commons-lang/download_lang.cgi

public static String[] split(String str, String separatorChars)

    String[] res = StringUtils.split("C450.00 C30 P100", "CP ");        
    for (String r : res) {
        System.out.println(r);
    }

Answer 5

I assume the separate 'numbers' are always in this format:

C130
P90
V2.0

that is, a single letter followed by a number (possibly with a floating point).

String input = "C450.00 C30 P100";

// First split the string by a space
String[] parts = input.split(" ");

for (String part : parts) {
    // Get the character from the string
    char ch = part.charAt(0);

    // Get the remains of the string and convert it to a double
    double number = Double.parseDouble(part.substring(1));

    // Then do something with 'ch' and 'number'
}

---

If the separate parts possibly have two or more letters in it, eg AC130 , then you need another approach:

String input = "AC130 AG36 P90";
String[] parts = input.split(" ");

for (String part : parts) {
    /* Do some regular expression magic. */
}

See http://www.vogella.com/tutorials/JavaRegularExpressions/article.html .

Answer 6

here some piece of code:

public static void main(String[] args) {

    String a = "C450.00 C30 P100";
    String letters = "";
    String numbers = "";

    for (int i = 0; i < a.length(); i++) {
        if ((a.charAt(i) + "").matches("\\d|\\.| ")) {
            numbers += a.charAt(i);
        } else {
            letters += a.charAt(i);
        }
    }
    String[] strArray = numbers.split(" ");
    int[] numberArray = new int[strArray.length];
    for (int i = 0; i < strArray.length; i++) {
        numberArray[i] = (int) Double.parseDouble(strArray[i]);
        System.out.println(numberArray[i]);
    }
    System.out.println(letters);
}

the result is numberArray , which contains all numbers as ints.
and letters , which is a String with all letters.