SQL Server : Select in Select

Question

I have something like this:

Select
    sum(spareparts), 
    month(calculationdate) 
from 
    cz_axnmrs_calculations 
where 
    CASE_ID in (select case_id 
                from cz_axnmrs_cases 
                where insurer_memberid = 'MM-O-5B57274F') 
    and YEAR(calculationdate)='2014'  
group by 
    month(calculationdate) DESC

It's cool but i need to edit it a bit more specific. Right it get data from all spareparts, and I need to get it just from LAST ONE! So instead of that to count 3 results via SUM just display LAST one

I try write one more select to sum brackets but it finish with error SQL syntax. Can somebody help me to write this statement?

Thanks

Answer 1

尝试将TOP 1添加到第一个SELECT

Answer 2

if you mean last one from the result you already got then-

SELECT TOP 1
    sum(spareparts), 
    month(calculationdate) 
from 
    cz_axnmrs_calculations 
where 
    CASE_ID in (select case_id 
                from cz_axnmrs_cases 
                where insurer_memberid = 'MM-O-5B57274F') 
    and YEAR(calculationdate)='2014'  
group by 
    month(calculationdate) 
ORDER month(calculationdate) desc

Answer 3

Either

SELECT TOP 1
    sum(spareparts), 
    month(calculationdate) 
FROM
    cz_axnmrs_calculations 
WHERE
    CASE_ID in (select case_id 
                from cz_axnmrs_cases 
                where insurer_memberid = 'MM-O-5B57274F') 
    and YEAR(calculationdate)='2014'  
GROU BVY 
    month(calculationdate) DESC

Or add another vale to the group by.... Memberid

Answer 4

If showing last row is what you want to do you can try these:

Use Order by <column> desc and then pick the 1st row using Top 1 .

You can also use ROW_NUMBER()