PostgreSQL get column with date + interval

Question

If I have table with a two columns:

• date (timestamp)
• milliseconds (int)

How could I write a query that would return the two columns and a third column that represents a sum of the first two as a timestamp.

Like this:

            date            | milliseconds  |              sum          
----------------------------+---------------+----------------------------
 2014-12-10 17:43:47.554989 |         11882 | 2014-12-10 17:43:59.436989

Thanks!

Answer 1

I think you answer is as follows:

# select date, milliseconds, date+milliseconds*interval '1 milliseconds' as sum from temp;

             date            | milliseconds |            sum
 ----------------------------+--------------+----------------------------
  2014-12-10 17:43:47.554989 |        11882 | 2014-12-10 17:43:59.436989
 (1 row)

I created a temp table with your timestamp field called date, and your int field called milliseconds. Then ran the above select off the table with your values in it. Hope this helps.

Answer 2

只需将其添加为间隔即可：

select stamp + (ms / 1000) * '1 second'::interval

Answer 3

您正在寻找的价值是

 date + milliseconds * INTERVAL '1 MILLISECOND';