I have list of lists like this:
l = [["08:00", "09:00", 60, False, 1.0],
["09:00", "10:00", 60, False, 0.3],
["12:00", "13:00", 60, False, 2.0],]
I want to check if list l
have a element but I don't know value of last float . I only know ["12:00", "13:00", 60, False, ]
.
if ["12:00", "13:00", 60, False, ???? ] in l:
pass
Do you have an idea?
You could create a dummy class which compares equal to everything. Then you can use it as a kind of wildcard in your in
condition.
class Dummy:
def __eq__(self, other):
return True
l = [["08:00", "09:00", 60, False, 1.0],
["09:00", "10:00", 60, False, 0.3],
["12:00", "13:00", 60, False, 2.0],]
if ["12:00", "13:00", 60, False, Dummy() ] in l:
print "found"
I'd do it this way:
# The input.
l = [["08:00", "09:00", 60, False, 1.0],
["09:00", "10:00", 60, False, 0.3],
["12:00", "13:00", 60, False, 2.0],]
# The pattern you want to match.
pattern = ["12:00", "13:00", 60, False]
# Make a list of all comparisons.
result = [pattern == e[:4] for e in l]
# Test.
if any(result):
pass
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