Select using LEFT OUTER JOIN with condition

Question

I have two tables Table A and Table B

Table A

1. *id*
2. *name*

Table B

1. *A.id*
2. *datetime*

I want to select

1. *A.id*
2. *A.name*
3. *B.datetime*

Even if table B do not contains a row with A.id for specific day and it should replace that column with NULL

eg

Table A contains

1. *(1 , Haris)*
2. *(2, Hashsim)*

Table B Contains following for today's date.

1. *(1, '2014-12-26 08:00:00')*

I should show 2 results with id 1 and 2 instead of only id 1 .

Using LEFT OUTER JOIN with WHERE Clause makes it a LEFT INNER JOIN, how to work around that ?

Answer 1

SELECT A.id, A.name, b.datetime
FROM A
LEFT Outer JOIN B on B.id = A.id

Answer 2

SELECT a.id, a.name, b.datetime
FROM A
LEFT JOIN B on B.aid = a.id
WHERE coalesce(B.datetie, '1900-01-01') < @MyDateTime

Answer 3

Use LEFT OUTER JOIN to get all the rows from Left table and one that does not have match will have NULL values in Right table columns

SELECT A.id,
       A.name,
       B.[datetime]
FROM   tableA A
       LEFT OUTER JOIN tableB B
                    ON A.Id = B.id
                       AND B.[datetime] < @date 

Answer 4

Select A.id,A.name,B.datetime 
from tableA A 
Left join
(
   SELECT B.ID,B.datetime 
   FROM tableB B
   WHERE B.datetime <= 'myDateTime'
)B
ON A.aid = B.id