Python Regex to match and exclude certain content

Question

I'm trying to exclude some content from a string. Here is an example:

Sony Xperia Z2 m/Smartwatch 2

and:

Sony Xperia Z2 + headphones

I want to get only

Sony Xperia Z2

in both cases.

I have been able to match the string i want to get rid of with this but how do i select the inverse? What i got so far:

 m/([a-zA-Z 0-9]*)

Edit: I have added another case.

Answer 1

Using regex split

re.split(r" m/| \+ ", yourString)[0]

This will work with both of your examples:

string1 = "Sony Xperia Z2 m/Smartwatch 2"
print re.split(" m/| \+ ", string1)[0]
# output: Sony Xperia Z2

string2 = "Sony Xperia Z2 + headphones"
print re.split(" m/| \+ ", string2)[0]
# output: Sony Xperia Z2

And if you have more separator characters, you can add them to the pattern of the split function.

You can also use re.split(...)[1] to retrieve the second part of your string:

string1 = "Sony Xperia Z2 m/Smartwatch 2"
print re.split(" m/| \+ ", string1)[1]
# output: Smartwatch 2

Answer 2

You can use:

>>> s = 'Sony Xperia Z2 m/Smartwatch 2'
>>> re.sub(r'\s*m/.*$', '', s)
'Sony Xperia Z2'

Answer 3

Using Regex

>>> re.findall(r"[a-zA-Z0-9 ]+(?= m/)", "Sony Xperia Z2 m/Smartwatch 2")
['Sony Xperia Z2']

---

>>> re.findall(r"[a-zA-Z0-9 ]+(?= m/)", "Sony Xperia Z2 m/Smartwatch 2")[0]
'Sony Xperia Z2'

Using Split

>>> "Sony Xperia Z2 m/Smartwatch 2".split(" m/")[0]
'Sony Xperia Z2'

Answer 4

Something like :

test = 'Sony Xperia Z2 m/Smartwatch 2'
res = re.search('m/([a-zA-Z 0-9]*)', test)
cleanstr = test.replace(res.group(), '')
print cleanstr

And you got Sony Xperia Z2