i have TXT file with football results in this format:
1-0
2-0
2-3
etc...
I want to count each result to know how much of them are in this file. I have code to count it:
def find_result(self):
file = open("results.txt", "r")
result_00 = 0
result_01 = 0
result_02 = 0
result_03 = 0
result_10 = 0
result_11 = 0
result_12 = 0
result_13 = 0
result_20 = 0
result_21 = 0
result_22 = 0
result_23 = 0
result_30 = 0
result_31 = 0
result_32 = 0
result_33 = 0
result_other = 0
results = 0
for line in file:
results += 1
line = line.rstrip()
if line == '0-0':
result_00 += 1
elif line == '0-1':
result_01 += 1
elif line == '0-2':
result_02 += 1
elif line == '0-3':
result_03 += 1
elif line == '1-0':
result_10 += 1
elif line == '1-1':
result_11 += 1
elif line == '1-2':
result_12 += 1
elif line == '1-3':
result_13 += 1
elif line == '2-0':
result_20 += 1
elif line == '2-1':
result_21 += 1
elif line == '2-2':
result_22 += 1
elif line == '2-3':
result_23 += 1
elif line == '3-0':
result_30 += 1
elif line == '3-1':
result_31 += 1
elif line == '3-2':
result_32 += 1
elif line == '3-3':
result_33 += 1
else:
result_other += 1
print('[0-0]' + str(result_00))
print('[0-1]' + str(result_01))
print('[0-2]' + str(result_02))
print('[0-3]' + str(result_03))
print('[1-0]' + str(result_10))
print('[1-1]' + str(result_11))
print('[1-2]' + str(result_12))
print('[1-3]' + str(result_13))
print('[2-0]' + str(result_20))
print('[2-1]' + str(result_21))
print('[2-2]' + str(result_22))
print('[2-3]' + str(result_23))
print('[3-0]' + str(result_30))
print('[3-1]' + str(result_31))
print('[3-2]' + str(result_32))
print('[3-3]' + str(result_33))
print('[OTHER]' + str(result_other))
print('Matches: ' + str(results))
I think it is not good way to do this (i mean too much code), is there any better solution to do this? Thank You
# import Counter for Counting the number of occurances of each items
from itertools import Counter
# Open the file for reading
with open("results.txt", "r") as input_file:
# Create the counter object with the lines read from the file
c = Counter(line.rstrip() for line in input_file)
# Print the actual item (key) and the number of occurances (count)
for key, count in c.items():
print("[{}] - {}".format(key, count))
# Find the total number of elements encountered, by adding all the counts
print(sum(c.values())
As a more pythonic way you can use collections.Counter
that is for this aim :
from collections import Counter
c_dic=Counter(open("results.txt", "r").readlines())
and you have a lot of choice for print your dictionary or items , as you have not a nested dictionary there is no need to loop over items and print them you can use json.dumps
for print the dictionary with arbitrary indent :
from collections import Counter
import json
print json.dumps(Counter(open("newefile.txt", "r").readlines()),indent=4)
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