Let's say I have the following code in a header:
class A {
public:
struct B {...}
...
}
Shouldn't I be able to make this declaration in a source that includes the above header file:
...
B structb;
...
without having to declare the scope I'm using? (A::B structb)
Thanks a lot.
通过显示的代码,它意味着B是A内的结构,就像A的任何其他属性一样。因此,如果不使用范围解析,就无法声明或使用该变量。
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