If and else statements in easyGUI?

Question

So i have a basic question: how to use if and else statements correctly with easyGUI? This is what I have:

import easygui

msg = "Oh i see m9, choos your difficulty"
title = "Mountain Dew Franchise"
choices = ["Pro 360 noscoper(+1001)", "Dank skrubl0rd(-666)"]
choice = easygui.ynbox(msg, title, choices)

#if choices==choices[0]:
    easygui.msgbox("Good choos m20, let the skrubl0rd noscoping begin.")

#if choices==choices[1]:
    easygui.msgbox("Oh i see m8.")

The # lines seem to be the problem area

It does not let me go to either msgbox, but instead just closes the program, any help would be appreciated.

Answer 1

The ynbox returns True or False , not one of your choices (that's just what it displays on the two buttons!). So, change your checks to if choice: and else: (and make sure your indentation's correct -- looks weird in your Q!-) and you should be fine.

Answer 2

choice = easygui.ynbox(msg, title, choices)

This ynbox returns True or False . That means that choice can only be one of these two values.

if choices==choices[0]:

You are comparing if your list ( choices ) is equal to the value of your first element in the same list.

---

To make your program work, you need to modify your if section a bit.

if choice:
     easygui.msgbox("Good choos m20, let the skrubl0rd noscoping begin.")
else:
     easygui.msgbox("Oh i see m8.")

Since choice can only be True or False and the first option in your choices list become the True value, this logic will work.

Answer 3

A simple Example it may helpful:

from easygui import *


msg  = "Flavor"
title = "survey"
choices = ["vanila", "chocolate", "foo","strbry"]
choice = choicebox(msg, title, choices)

if choice == "foo":
   print "your choice is good" 
else:
   print "Try again its not a good choice !"