How to replace part of a String in Java?

Question

Im trying to replace part of a String based on a certain phrase being present within it. Consider the string "Hello my Dg6Us9k. I am alive." .

I want to search for the phase "my" and remove 8 characters to the right, which removes the hash code. This gives the string "Hello. I am alive." How can i do this in Java?

Answer 1

Im trying to replace part of a String based on a certain phrase being present within it. Consider the string "Hello my Dg6Us9k. I am alive." .

I want to search for the phase "my" and remove 8 characters to the right, which removes the hash code. This gives the string "Hello. I am alive." How can i do this in Java?

Answer 2

Im trying to replace part of a String based on a certain phrase being present within it. Consider the string "Hello my Dg6Us9k. I am alive." .

I want to search for the phase "my" and remove 8 characters to the right, which removes the hash code. This gives the string "Hello. I am alive." How can i do this in Java?

Answer 3

Im trying to replace part of a String based on a certain phrase being present within it. Consider the string "Hello my Dg6Us9k. I am alive." .

I want to search for the phase "my" and remove 8 characters to the right, which removes the hash code. This gives the string "Hello. I am alive." How can i do this in Java?

Answer 4

Im trying to replace part of a String based on a certain phrase being present within it. Consider the string "Hello my Dg6Us9k. I am alive." .

I want to search for the phase "my" and remove 8 characters to the right, which removes the hash code. This gives the string "Hello. I am alive." How can i do this in Java?

Answer 5

Im trying to replace part of a String based on a certain phrase being present within it. Consider the string "Hello my Dg6Us9k. I am alive." .

I want to search for the phase "my" and remove 8 characters to the right, which removes the hash code. This gives the string "Hello. I am alive." How can i do this in Java?