How to Convert NSNumber in Objective C to Java Long

Question

NSNumber *idValue =[NSNumber numberWithLong:[result longLongValue]];

Above result value is "2174767089" , idValue is "-2120200207" .It got converted.

By mistake I sent this NSNumber to my Server.

Accepting Param in Server (Java Servlet) is Long. In Java Service, I am getting "-2120200207" . Wanted to convert this back to "2174767089" . How is it possible?

Answer 1

我认为您可以使用BigInteger类型，但是您需要使用大整数等值类型（如果您正在使用数据库）来更改数据库。

Answer 2

You appear to want to construct an NSNumber with a longLongValue , but the constructor you're calling is for a longValue .

NSNumber *idValue =[NSNumber numberWithLongLong:[result longLongValue]];
if ([idValue longLongValue] == [result longLongValue]) {
  NSLog(@"Of course it does.");
}

Incidentally, a Java Long is the same length as an Objective-C long long : 64 bits. An Objective-C long is a pseudonym for int .