Popping out tuples in a list of tuples that match neighbor list of tuples

Question

One list of tuples reads:

[(5,), (4,), (7,)]

The second one reads:

[(7,'James',6,1), (3,'Don',4,3), (2,'Poppy',5,1), (4,'Dom',6,4)]

I wish to pop out tuples in the second list if the first element is to be found on the first list. Ie, returning the second list as follows:

[(3,'Don',4,3), (2,'Poppy',5,1)]

Answer 1

In [32]: list1 = [(5,), (4,), (7,)]

In [33]: list2 = [(7,'James',6,1), (3,'Don',4,3), (2,'Poppy',5,1), (4,'Dom',6,4)]

In [34]: [ x for x in list2 if x[:1] not in list1]
Out[34]: [(3, 'Don', 4, 3), (2, 'Poppy', 5, 1)]

Answer 2

>>> x = [(5,), (4,), (7,)]
>>> y = [(7,'James',6,1), (3,'Don',4,3), (2,'Poppy',5,1), (4,'Dom',6,4)]
>>> set_x = set(x)
>>> y[:] = [t for t in y if t[:1] not in set_x]
>>> y
[(3, 'Don', 4, 3), (2, 'Poppy', 5, 1)]