Append every other line from a text file? (Python)

Question

What I'm trying to do is append every other line in my text file into a list, and then the other lines into a serperate list? Eg

Text File 'example'

Item 1
Item 2
Item 3
Item 4
Item 5

So I want 'Item 1', 'Item 3' and 'Item 5' in a list called exampleOne and the other items in a list called exampleTwo?

I've tried for ages to try and work this out by myself by slicing and then appending in different ways, but I just can't seem to get it, if anyone could help it would be greatly appreciated!

Answer 1

from itertools import izip_longest as zip2
with open("some_file.txt") as f:
    linesA,linesB = zip2(*zip(f,f))

is one way you could do something like this

this basically is just abusing the fact that filehandles are iterators

Answer 2

What about

with open('example') as f:
    lists = [[], []]
    i = 0
    for line in f:
        lists[i].append(line.strip())
        i ^= 1

print(lists[0])  # ['Item 1', 'Item 3', 'Item 5']
print(lists[1])  # ['Item 2', 'Item 4']

Or simpler, with enumerate:

with open('example') as f:
    lists = [[], []]
    for i,line in enumerate(f):
        lists[i%2].append(line.strip())

print(lists[0])  # ['Item 1', 'Item 3', 'Item 5']
print(lists[1])  # ['Item 2', 'Item 4']

EDIT

print(lists[0][0])  # 'Item 1' 
print(lists[0][1])  # 'Item 3'
print(lists[0][2])  # 'Item 5'
print(lists[1][0])  # 'Item 2'
print(lists[1][1])  # 'Item 4'