I want to remove only 5 characters from a string after the occurrence of "\\"(double back slash). For example:-
String s = ":zap:\\ufe0f:umbrella:\\ufe0f:snowflake:\\ufe0f:snowman:\\ufe0f:cyclone:" ;
The output should be :
:zap::umbrella::snowflake::snowman::cyclone:
So, in the above string the 5 letters after the \\ (double back slash) has been removed. How can I achieve this ?
I tried some code but no luck. :(
\️
is an unicode which represents a single character.
This code will remove any character but not of a word character or colon.
String s = ":zap:\ufe0f:umbrella:\ufe0f:snowflake:\ufe0f:snowman:\ufe0f:cyclone:" ;
System.out.println(s.replaceAll("[^\\w:]", ""));
Output:
:zap::umbrella::snowflake::snowman::cyclone:
You can try this Regex "/\\\\.{5}/g"
with the replaceAll() method:
String s = ":zap:\ufe0f:umbrella:\ufe0f:snowflake:\ufe0f:snowman:\ufe0f:cyclone:" ;
s=s.replaceAll("/\\.{5}/g", "");
Here is a DEMO of the Regex .
it matches any character exactly 5 times after the
\\
.
It gives this output:
:zap:️:umbrella:️:snowflake:️:snowman:️:cyclone:
You can try The working Example here
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