I have a MySQL database and it has a signUp table. The table has a field called created which is a placeholder for signups date. Format is eg: [2014-10-12 17:48:24].
There are many user who signup in single day. I am trying to get a count of each day signups.
My code below displays single date eg: [20141012000000] but the count is still 1.
SELECT DISTINCT TRUNCATE(created,-6) as created,
COUNT(*) as CountCreated
FROM signUp
WHERE created >= '20000101000000' AND created <= '30000101000000'
GROUP BY created
---SQL RESULT---
|------------------------|-------------------------|
|Created CountCreated
|------------------------|-------------------------|
|20141012000000 1
|------------------------|-------------------------|
|20141015000000 1
|------------------------|-------------------------|
There are more than 30 signup for that date. I used truncate so that the value is compared at the WHERE statement and its ommiting the TIME and only returning DATE . The time is zeroed.
What I am trying to get:
I simply want to get the total count of created field for that date. For example my signUp for [20141012000000] is 30 so I need it like this
|------------------------|-------------------------|
|Created CountCreated
|------------------------|-------------------------|
|20141012000000 30
|------------------------|-------------------------|
|20141015000000 33
|------------------------|-------------------------|
Please help me fix this...
Thank You.
Assuming created
is datetime
:
SELECT date(created) as created, COUNT(*) as CountCreated
FROM signUp
GROUP BY date(created);
If it is a string:
SELECT left(created, 10) as created, COUNT(*) as CountCreated
FROM signUp
GROUP BY left(created, 10);
You'd also have to group by the truncated value in that scenario, and then get rid of the distinct. But a better option would simply be to make the created field a timestamp, and then use date(created).
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.