How to format list output in python

Question

I am trying to format output of an index and list from this:

[6]
[7]
[8]
[9]
The answers should be: 
['b', 'c', 'a', 'c']`

To more like this:

[6]  b   
[7]  c
[8]  a    
[9]  c

Here is the code snippet:

print( "Here are the questions the you got wrong: ")
for i in range (0, 10):
    if q[i] != answers[i]:
        print ( [i+1],)
    else:
        ("You got all of the questions correct, Good Job. ")
print("The answers should be: ")
print(wrongList)

Answer 1

You didn't collect the wrongList but it'll be easy to do with:

print("The answers should be: ")
for i in range (0, 10):
    if q[i] != answers[i]:
        print (q[i], answers[i])

Answer 2

Just print answers[i] :

for i in range (10):
    print("[{}] {}".format(i+1, answers[i])

If there are only ten answers you can use enumerate with a starting value of 1, enumerate(answers, start=1) or if there are more the than ten you will have to slice it:

 for i  answer in enumerate(answers[:10], start=1)

You can also zip and forget indexing:

for i, (a, b) in enumerate(zip(answers, p),1):
    if a != b:
       print("[{}] {}".format(count, a))
    else:
       print("You got all of the questions correct, Good Job. ")

"[{}] {}".format(count, a) is using str.format which is generally the preferred method.

Answer 3

You can use enumerate to loop through a list and get the index:

for i, answer in enumerate(answers):
    print("[%s] %s" % (i, answer))

If the print statement doesn't make sense, take a look at the documentation for string formatting .