How do I remove whole sub-list from list, if i have only few element of the sub-list? python

Question

I'm trying to remove sub-list from list and gets this error: ValueError: list.remove(x): x not in list

I wish to remove the sub-list despite the fact that x have only few elemnt from sub-string

something like that:

list_a=[[1,2,3],[4,5,6]]

list_a.remove([1,3])

list_a

[4,5,6]

---

From comments below:

i got list of products:

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

lst[0] , lst[2] and lst[3] are unique for each product. i wish to remove the whole sub list, by having this three elemnts like:

>>> products.remove(['0001', 'Food', 'ISR'])
>>> products
['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']

.

def del_product(depot, product_data):
'''
    del_product
    delets a validated product data from the depot
    if such a product does not exist in the depot
    then no action is taken

    arguments:
    depot - list of lists
    product_data - list

    return value: boolean
'''

# Your code goes her

if validate_product_data(product_data)==True:
    for product in depot:
        if equal_products(product, product_data)==True:
            rem = set(product_data)
            for x in reversed(depot):
                if rem.issubset(x):
                    depot.remove(x)

            return True
        else:
            continue
    return False

Answer 1

You can check if [1,3] is a subset with set.issubset :

list_a = [[1,2,3],[4,5,6]]

rem = set([1,3])

list_a[:] = [ x for x in list_a if not rem.issubset(x)]
print(list_a)

s.issubset(t) s <= t test whether every element in s is in t

Using list_a[:] changes the original list.

With your products list it is exactly the same:

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

rem = set(['0001', 'Food', 'ISR'])

products[:] = [ x for x in products if not rem.issubset(x)]
print(products)
[['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

Using a loop if it makes it easier to follow, you can combine reversed and issubset:

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

rem = set(['0001', 'Food', 'ISR'])   

for x in reversed(products):
    if rem.issubset(x):
        products.remove(x)
print(products)

Answer 2

>>> list_a = [[1,2,3],[4,5,6]]
>>> bad = [1,3]
>>> list_a = [l for l in list_a if all(e not in l for e in bad)]
>>> list_a
[[4, 5, 6]]

Now that the actual question has been revealed:

>>> products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]
>>> to_remove=['0001', 'Food', 'ISR']
>>> products = [l for l in products if [l[0], l[2], l[3]] != to_remove]
>>> products
[['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

It might be good to move to an OO approach, with a Product or Food object containing code , name , category , label , and date attributes.

Answer 3

list_a = [sub for sub in list_a if not all(i in [1, 3] for i in sub)]