This is what I want, but for an integer. I am not allowed to use break
or continue
to exit loops.
# basically I need this, but with an int(input('please enter a number'))
ask = input('Would you like to play Steal or Deal [y|n]? ')
while ask not in ('y', 'n'):
print ("Please enter either 'y' or 'n'")
print('')
ask = input('Would you like to play Steal or Deal [y|n]? ')
You could try to convert the string to an int and catch the exception:
def is_number(s):
try:
int(s)
return True
except ValueError:
return False
ask = input('please enter a number: ')
while not is_number(ask):
print ("no, a number!")
print('')
ask = input('please enter a number: ')
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