How to take input after getline

Question

#include <iostream>
#include <string>
using namespace std;

struct Student
{
    int ID;
    long phno;
    string name;
    string depart;
    string email;
};

int main ()
{
    Student S1 ;

    cout << "\n=======================================================\n" ;

    cout << "Enter ID no. of student 1       : " ; cin >> S1.ID ;
    cout << "Enter name of student 1         : " ; getline(cin, S1.name) ; cin.ignore();
    cout << "Enter department of student 1   : " ; getline(cin, S1.depart) ; cin.ignore();
    cout << "Enter email adress of student 1 : " ; getline(cin, S1.email) ; cin.ignore();
    cout << "Enter phone number of student 1 : " ; cin >> S1.phno ;     

    return 0;
}

The problem is that it's not taking input after email adress the program is ignoring to take input in phno, directly exit after emailadress.

Answer 1

I made some slight modifications to your code.

Note that I only call cin.ignore() after I use cin directly on a variable ( cin >> S1.ID or cin >> S1.phno ).

This is because when you use cin on an int, it leaves the \\n in the buffer. When you later call getline(cin,...) you just suck up that leftover \\n , and that's considered your whole "line."

A working example is available here .

#include <iostream>
#include <string>
using namespace std;

struct Student
{
    int ID;
    long phno;
    string name;
    string depart;
    string email;
};

int main ()
{
    Student S1 ;

    cout << "\n=======================================================\n" ;

    cout << "Enter ID no. of student 1       :\n" ;
    cin >> S1.ID ; 
    cin.ignore();

    cout << "Enter name of student 1         :\n" ;
    getline(cin, S1.name) ; 

    cout << "Enter department of student 1   :\n" ;
    getline(cin, S1.depart) ;

    cout << "Enter phone number of student 1 :\n" ;
    cin >> S1.phno ;
    cin.ignore();

    cout << "Enter email adress of student 1 :\n" ;
    getline(cin, S1.email) ;    

    cout << endl << endl;

    cout << S1.ID << endl << S1.name << endl << S1.depart << endl << S1.phno << endl << S1.email << endl;

    return 0;
}