Code description
mydic={node.getId():(round(x0),round(y0))}
print mydic.items()
output = open('output.txt', 'ab+')
for key, value in mydic.items():
output.write(str(key))
output.write(str(value))
output.write("\n")
output.close()
Output-text file
Deepu(794.0, 586.0)
Facebook(800.0, 329.0)
LinkedIn(789.0, 768.0)
Google+(502.0, 671.0)
Viber(716.0, 559.0)
GoogleTalk(1093.0, 678.0)
Plus2(1072.0, 239.0)
Btech(534.0, 253.0)
Mtech(788.0, 136.0)
Desired Output (how is it possible-please help)
Deepu 794 586
Facebook 800 329
LinkedIn 789 768
Google+ 502 671
Viber 716 559
GoogleTalk 1093 678
Plus2 1072 239
Btech 534 253
Mtech 788 136
将for循环中的output.write()
行更改为此:
output.write("{0} {1} {2}\n".format(str(key), str(value[0]), str(value[1]))
A little more pythonic with itertools.chain and join : Also note the conversion to ints.
mydic={
"Deepu":(794.0, 586.0),
"Facebook":(800.0, 329.0),
"LinkedIn":(789.0, 768.0),
"Google+":(502.0, 671.0),
"Viber":(716.0, 559.0),
"GoogleTalk":(1093.0, 678.0),
"Plus2":(1072.0, 239.0),
"Btech":(534.0, 253.0),
"Mtech":(788.0, 136.0)
}
from itertools import chain
print "\n".join(" ".join(chain([key],[str(int(number)) for number in value])) for key,value in mydic.items())
Output:
Viber 716 559
Google+ 502 671
Facebook 800 329
LinkedIn 789 768
Plus2 1072 239
Mtech 788 136
Btech 534 253
Deepu 794 586
GoogleTalk 1093 678
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