Regex in VBA.
I am using the following regex to match the second occurance of a 4-digit group, or the first group if there is only one group:
\b\d{4}\b(?!.+\b\d{4}\b)
Now I need to do kind of the opposite: I need to match everything up until the second occurance of a 4-digit group, or up until the first group if there is only one. If there are no 4-digit groups, capture the entire string.
This would be sufficient.
But there is also a preferable "bonus" route: If there exists a way to match everything up until a 4-digit group that is optionally followed by some random text, but only if there is no other 4-digit group following it. If there exists a second group of 4 digits, capture everything up until that group (including the first group and periods, but not commas). If there are no groups, capture everything. If the line starts with a 4-digit group, capture nothing.
I understand that also this could (should?) be done with a lookahead, but I am not having any luck in figuring out how they work for this purpose.
Examples:
Input: String.String String 4444
Capture: String.String String 4444
Input: String4444 8888 String
Capture: String4444
Input: String String 444 . B, 8888
Capture: String String 444 . B
Bonus case:
Input: 8888 String
Capture:
Matches everything except spaces till last occurace of a 4 digit word
You can use the following:
(?:(?! ).)+(?=.*\b\d{4}\b)
See DEMO
For your basic case (marked by you as sufficient), this will work:
((?:(?!\d{4}).)*(?:\d{4})?(?:(?!\d{4}).)*)(?=\d{4})
You can pad every \\d{4}
internally with \\b
if you need to.
See a demo here .
You can use this regex in VBA to capture lines with 4-digit numbers, or those that do not have 4-digit numbers in them:
^((?:.*?[0-9]{4})?.*?(?=\s*?[0-9]{4})|(?!.*[0-9]{4}).*)
See demo , it should work the same in VBA.
The regex consists of 2 alternatives: (?:.*?[0-9]{4})?.*?(?=\\s*?[0-9]{4})
and (?!.*[0-9]{4}).*
.
(?:.*?[0-9]{4})?.*?(?=\\s*?[0-9]{4})
matches 0 or more (as few as possible) characters that are preceded by 0 or 1 sequence of characters followed by a 4-digit number, and are followed by optional space(s) and 4 digit number.
(?!.*[0-9]{4}).*
matches any number of any characters that do not have a 4-digit number inside.
Note that to only match whole numbers (not part of other words) you need to add \\b
around the [0-9]{4}
patterns (ie \\b[0-9]{4}\\b
).
If anyone is interested, I cheated to fully solve my problem.
Building on this answer , which solves the vast majority of my data set, I used program logic to catch some rarely seen use-cases. It seemed difficult to get a single regex to cover all the situations, so this seems like a viable alternative.
Problem is illustrated here .
The code isn't bulletproof yet, but this is the gist:
Function cRegEx (str As String) As String
Dim rExp As Object, rMatch As Object, regP As String, strL() As String
regP = "^((?:.*?[0-9]{4})?.*?(?:(?=\s*[0-9]{4})|(?:(?!\d{4}).)*)|(?!.*[0-9]{4}).*)"
' Encountered two use-cases that weren't easily solvable with regex, due to the already complex pattern(s).
' Split str if we encounter a comma and only keep the first part - this way we don't have to solve this case in the regex.
If InStr(str, ",") <> 0 Then
strL = Split(str, ",")
str = strL(0)
End If
' If str starts with a 4-digit group, return an empty string.
If cRegExNum(str) = False Then
Set rExp = CreateObject("vbscript.regexp")
With rExp
.Global = False
.MultiLine = False
.IgnoreCase = True
.Pattern = regP
End With
Set rMatch = rExp.Execute(str)
If rMatch.Count > 0 Then
cRegEx = rMatch(0)
Else
cRegEx = ""
End If
Else
cRegEx = ""
End If
End Function
Function cRegExNum (str As String) As Boolean
' Does the string start with 4 non-whitespaced integers?
' Return true if it does
Dim rExp As Object, rMatch As Object, regP As String
regP = "^\d{4}"
Set rExp = CreateObject("vbscript.regexp")
With rExp
.Global = False
.MultiLine = False
.IgnoreCase = True
.Pattern = regP
End With
Set rMatch = rExp.Execute(str)
If rMatch.Count > 0 Then
cRegExNum = True
Else
cRegExNum = False
End If
End Function
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