I have a list with two item, each item is a dictionary. now I want to print the item but as these are dicts, python writes the dicts and not the name. any suggestion?
sep_st = {0.0: [1.0, 'LBRG'], 0.26: [31.0, 'STIG']}
sep_dy = {0.61: [29.0, 'STIG'], 0.09: [25.0, 'STIG']}
sep = [sep_st, sep_dy]
for item in sep:
for values in sorted(item.keys()):
p.write (str(item)) # here is where I want to write just the name of list element into a file
p.write (str(values))
p.write (str(item[values]) +'\n' )
My suggestion is that you use a dict for sep, instead of a list. That way you could make the dict names as string-keys for them:
sep_st = {0.0: [1.0, 'LBRG'], 0.26: [31.0, 'STIG']}
sep_dy = {0.61: [29.0, 'STIG'], 0.09: [25.0, 'STIG']}
sep = {"sep_st": sep_st, "sep_dy": sep_dy} # dict instead of list
for item in sep:
for values in sorted(sep[item].keys()):
p.write (str(item))
p.write (str(values))
p.write (str(sep[item][values]) +'\n')
As you can see in this other question , it's impossible to access instance names, unless you subclass dict and pass a name to the constructor of your custom class, so that your custom dict instance can have a name that you can have access to.
So in that case, I suggest that you use dicts with name-keys to store your dicts, instead of a list.
As sep
is a list of variables
storing the dictionaries
, when you try to print sep
you will print the dictionaries
.
If you really need to print each variable
name as a string
, one way to do that is this to also create an other list
with the variable
names as strings:
sep_st = {0.0: [1.0, 'LBRG'], 0.26: [31.0, 'STIG']}
sep_dy = {0.61: [29.0, 'STIG'], 0.09: [25.0, 'STIG']}
sep = [sep_st, sep_dy]
sep_name = ['sep_st', 'sep_dy']
for i in sep_name:
print i
Then you can do the rest of your code.
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