Count Delimiter in a string in Java

Question

i have a string in Java.

1|2|3|4|5|2|2|3|4|123441|234556|67783|56764|55454

i want to count a delimiter above string . Please help me in how to count and i want only starting 7 Delimiter value.

Answer 1

You can split using | character.

public static void main(String[] args) {
    String s = "1|2|3|4|5|2|2|3|4|123441|234556|67783|56764|55454";
    String[] strArr = s.split("\\|");
    System.out.println("Array : " + Arrays.toString(strArr));
    System.out.println("Delimiter count : " + (strArr.length - 1)); // Prints 13
    System.out.println("7th field : " + strArr[7]); // Prints 3
}

Answer 2

You can solve it with regular expressions, using Pattern and Matcher classes:

    String s = "1|2|3|4|5|2|2|3|4|123441|234556|67783|56764|55454";
    Pattern p = Pattern.compile("((\\d+\\|){7}).*");
    Matcher m = p.matcher(s);
    if (m.matches()) {
        System.out.println(m.group(1));
    }

To understand the code above, have a look at regular expressions, eg http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html

Answer 3

In case if your input string if sthg like this:-

1|2|3|4|5|2|2|3|4|123441|234556|||

having empty values between delimiters. Then you can go with a different version of split function.

String[] strArr = s.split("\\|", -1);

You need to pass -1 as the second argument to split otherwise it removes empty strings.