New textfile every time run with Python

Question

How can I create a new text file every time I run the following program? I want to collect data, every 5 secs, but I don't want to overwrite the first text file. I use also a time.sleep(5) function.

fobj_out = open("Tabelle.txt", "w")                                 
fobj_out.write("Orte chron.: [Höhe in m, Temp. in °C, rel. Feuchte in %, Niederschlag in mm, Sonnenschein in %]\n")

for key in sorted(unserdictionary.iterkeys()):                      
    print("%s: %s" % (key, unserdictionary[key]))                   
    fobj_out.write("%s: %s\n" % (key, unserdictionary[key]))
fobj_out.close

Is there a simple way?

Answer 1

You can get the current time, and append it to the file name.

from time import gmtime, strftime
actual_time = strftime("%Y-%m-%d %H-%M-%S", gmtime())

fobj_out = open("Tabelle - " + str(actual_time) + ".txt", "w")                                 
fobj_out.write("Orte chron.: [Höhe in m, Temp. in °C, rel. Feuchte in %, Niederschlag in mm, Sonnenschein in %]\n")

for key in sorted(unserdictionary.iterkeys()):                      
    print("%s: %s" % (key, unserdictionary[key]))                   
    fobj_out.write("%s: %s\n" % (key, unserdictionary[key]))
fobj_out.close

You will get outputs as follows:

Tabelle - 2015-01-01 21-15-13.txt
Tabelle - 2015-01-01 21-20-13.txt

Answer 2

You can get the current time and then append that to the filename , you can use time module to get the time. Code would be like -

from time import time 
s = str(round(time() * 1000))
fobj_out = open("Tabelle" + s + ".txt", "w")

Answer 3

First check if the file already exists and then either create it or just append to the already existing file.

import os.path

if(os.path.isfile("Tabelle.txt")):
    obj_out = open("Tabelle.txt", "a")   # Append to the file
else:
    obj_out = open("Tabelle.txt", "w")   # create the file

# do the rest here....