SQL Query to distance traveled in a day based on timestamp and lat long

Question

I have a table with Date and latitude, longitude values in each row. I want a sql query to calculate the distance travailed in a day.

Say for date 2013-03-01 I want the total distance traveled,

ID      DATE                  LAT     LONG    V_ID
---------------------------------------------------
123     2013-03-01 06:05:24   45.544  86.544   1
124     2013-03-01 06:15:17   45.676  86.676   1 
125     2013-03-01 06:25:24   46.544  86.544   2
126     2013-03-01 06:38:14   46.651  86.651   2
127     2013-03-02 07:12:04   46.876  86.876   1 
128     2013-03-02 10:38:14   46.871  86.871   1
129     2013-03-02 10:56:14   46.871  86.671   2
130     2013-03-02 15:28:02   46.243  86.871   2

To calculate the distance what I wrote a sql function :

CREATE FUNCTION [dbo].[fnCalcDistanceKM](@lat1 FLOAT, @lat2 FLOAT, @lon1 FLOAT, @lon2 FLOAT)
 RETURNS FLOAT 
AS
BEGIN

RETURN ACOS(SIN(PI()*@lat1/180.0)*SIN(PI()*@lat2/180.0)+COS(PI()*@lat1/180.0)*COS(PI()*@lat2/180.0)*COS(PI()*@lon2/180.0-PI()*@lon1/180.0))*6371
END

but I want the total distance traveled in a day and for day 2013-03-01 I have top four row and I want total distance traveled in 2013-03-01

and similar to this date 2013-03-02 has last four row , how do I calculate distance for these rows.

Answer 1

You can use self join with ROW_NUMBER() to get distance travelled like this.

SQL Fiddle

Query

;WITH CTE AS 
(
SELECT *,CONVERT(DATE,[Date]) as tday,ROW_NUMBER()OVER(PARTITION BY CONVERT(DATE,[Date]) ORDER BY [Date] ASC) rn
FROM Travel
)
    SELECT T1.tday,SUM([dbo].[fnCalcDistanceKM](T1.lat,T2.lat,T1.long,T2.long)) as dist
    FROM CTE T1
    INNER JOIN CTE T2
        ON T1.tday = T2.tday
        AND T1.rn  = T2.rn -1
    GROUP BY T1.tday

Output

|       tday |               dist |
|------------|--------------------|
| 2013-03-01 | 129.40048639456964 |
| 2013-03-02 |  87.36216677343607 |