Php, var_export minifier

Question

lets say I have an output of var_export:

return array (
  'DatabaseMySQL_settings' => 
  array (
    'absPath' => 'C:/Dolgok/WEBprogramozas/_common/plugins/_framework/core/DatabaseMySQL_settings.php',
    'namespace' => '',
    'implements' => 
    array (
    ),
    'extendsFrom' => 'Framework_setting',
    'type' => 'C',
    'isAbstract' => false,
  ),

instead, I want to get this:

return array('DatabaseMySQL_settings'=>array('absPath'=>'DatabaseMySQL_settings.php','namespace'=>'','implements'=>array(),'extendsFrom'=>'Framework_setting','type'=>'C','isAbstract'=>false,),

So there is no newlines and spaces. How to achieve this?

Answer 1

如果您想要的输出仅在以后用于PHP，建议您使用serialize()代替

Answer 2

在PHP文档注释部分中检查此函数（ var_export_min ）： http : var_export_min