i have tried this code but getting no of applications only please help me thanks in advance
SELECT PositionName,
(SELECT COUNT(ApplicationNo) FROM APPLICATION) AS
NoOfApplications,
(SELECT COUNT(ApplicationNo)
FROM APPLICATION
WHERE EligibleStatus1=1 AND
EligibleStatus2=1) AS Qualified,
(SELECT COUNT(ApplicationNo)
FROM APPLICATION
WHERE EligibleStatus1=2 OR
EligibleStatus2=2) AS DisQualified
FROM APPLICATION
GROUP BY PositionName ORDER BY PositionName
PositionName Elligible Disqualified NoOfApplications
A 3 4 7
B 3 4 7
C 3 4 7
PositionName Elligible Disqualified NoOfApplications
A 1 2 3
B 1 1 2
C 1 1 2
SELECT a.PositionName,COUNT(a.ApplicationNo) AS
NoOfApplications,apl1.Qualified,apl2.DisQualified
FROM APPLICATION a
INNER JOIN (
SELECT PositionName, COUNT(ApplicationNo) AS Qualified
FROM APPLICATION
WHERE EligibleStatus1=1 AND
EligibleStatus2=1
GROUP BY PositionName
)apl1 ON a.PositionName=apl1.PositionName
INNER JOIN (
SELECT PositionName, COUNT(ApplicationNo) AS DisQualified
FROM APPLICATION
WHERE EligibleStatus1=1 AND
EligibleStatus2=1
GROUP BY PositionName
)apl2 ON a.PositionName=apl2.PositionName
GROUP BY PositionName ORDER BY PositionName
SELECT Positionname,
Count(NoOfApplication) AS NoOfApplications,
Max(COUNT1) AS Qualified,
Max(COUNT2) AS Diqualified
FROM APPLICATION A
CROSS APPLY (SELECT Count(NoOfApplication) AS COUNT1
FROM APPLICATION A
WHERE EligibleStatus1 = 1
AND EligibleStatus2 = 1)B
CROSS APPLY (SELECT Count(NoOfApplication) AS COUNT2
FROM APPLICATION A
WHERE EligibleStatus1 = 2
OR EligibleStatus2 = 2)C
GROUP BY PositionName
as you are looking for Summary result then by using Case and Sum we can get desired Result basing on your assumpted Data
select PositionName,
sum(case when EligibleStatus1 = 1 AND EligibleStatus2=1 then 1 else 0 end) AS Qualified,
sum(case when EligibleStatus1 = 2 OR EligibleStatus2=2 then 1 else 0 end) AS DisQualified,
count(ApplicationNo)
from APPLICATION
GROUP BY PositionName
ORDER BY PositionName
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