how can i search a text file of list of words from user input and print the line which contains these words?

Question

My query here is I want to search words from a text file and print those lines which contain those words. All the words are given as user input. Somehow I reached till this point it's is giving output as nothing.

def sip(x): 
    print("====Welcome to SIP log Debugger ==== ")
    file= input("Please Enter log File path: ")
    search = input("Enter the Errors you want to search for(seperated with commas):   ")
    search = [word.strip() for word in search.lower().split(",")]
    with open(file,'r') as f:
        lines = f.readlines()
        line = f.readline()
        for word in line.lower().split():
            if word in line:
                print(line),
                if word == None:
                    print('')

Answer 1

You're reading all the lines and saving them into a variable:

lines = f.readlines()

Then you try to read one more line:

line = f.readline()

But you've already read through the whole file, so there's nothing to read anymore, thus f.readline() returns '' . Next you try to loop through each word in the line variable, which is just '' .

Instead of all this, you should just loop through all the lines using for line in f: , so something like:

with open(file, 'r') as f:
    for line in f:
        line = line.lower()
        for word in search:
            if word in line:
                print(line)

I'm not sure what you're trying to do with the if word == None: , the word can never be None since line is a string and word is part of that string (you used line.split() ).