Skip line with a specific string from a file - Batch script

Question

I am trying to copy part of abc.txt to def.txt file using windows batch scripting.

abc.txt

Connected to: Oracle Database 11g Enterprise Edition Release 
11.2.0.4.0 - 64bit Production. With the Partitioning, Automatic Storage
Management, OLAP, Data Mining and Real Application Testing options.

About to export specified tables via Conventional Path ...
... exporting table             table_1      2000 rows exported
..... exporting table             table_2        456512 rows exported
. . exporting table             table_3   So on...
Export successful with warnings. table_1 has some issue.

def.txt

Connected to: Oracle Database 11g Enterprise Edition Release 
11.2.0.4.0 - 64bit Production. With the Partitioning, Automatic Storage
Management, OLAP, Data Mining and Real Application Testing options.

About to export specified tables via Conventional Path ...
Export successful with warnings. table_1 has some issue.

In short I want to skip the lines that are having the string "exporting" and move the result to def.txt. I tried using for /F but could not acheive this. Could you please help. Thanks in advance.

Answer 1

findstr /v /c:"exporting" abc.txt > def.txt

No need to iterate over the file. Just filter the lines in the input file that does not match ( /v ) the condition of containing the indicated literal, and send the output to the indicated file.

edited to adapt to comments

@echo off
    setlocal enableextensions disabledelayedexpansion
    > def.txt (
        for /f "tokens=1,* delims=:. " %%a in ('
            findstr /n "^" abc.txt
        ') do echo(%%b
    )

Here the file is processed by findstr to number the lines (to preserver empty lines in source file), the output processed by a for /f command with delims and tokens clauses configured to remove starting spaces/dots/colons in output lines.

Answer 2

这与MC ND的解决方案并没有什么不同-尽管这是另一个选择：目前区分大小写，但是有一个/i开关可以更改它。

find /v "exporting" < abc.txt > def.txt