Deleting items from a list with a less than operator

Question

I am working on a program for a class which has us build a craigslist type of program.

myStr=[]
b = "bike"
ans = True
while ans:
    print "1. Add an item"
    print "2. Find an item"
    print "3. Print the message board"
    print "4. Quit"
    choice = input("Enter your selection: ")
    if choice == 1:
        itemType = raw_input("Enter the item type-b,m,d,t,c: ")
        itemCost = input("Enter the item cost: ")
        myStr.append([itemType,itemCost])
    if choice == 2:
        itemType = raw_input("Enter the item type-b,m,d,t,c: ")
        maximum = input("Enter the maximum item cost: ")
        print maximum
    if choice == 3:
        print myStr
    if choice == 4:
        break

Fairly easy to read what's going on here but I am missing a crucial part which is deleting entries from myStr. I tried using a for loop but it did not work. What I need it to do is delete the first entry that meets this criteria. if maximum > itemCost then delete the first item in the list . I can't wrap my brain around it so any help would be great.

Also, any other advice to improve my code is welcome!

Answer 1

You could try something extracting the list of items whose cost is greater than maximum and then removing those items from your list. List comprehension is great at it.

max_cost = 3
myStr = [['Item1', 2], ['Item2', 3], ['Item3', 4]]
to_remove = [item for item in myStr if item[1] > max_cost]
for item in to_remove:
    myStr.remove(item)

You could try with something like that.