In Firefox, this code works like a charm...but in Safari, it doesn't execute...where am I going wrong?
$('#ul_stages li.stage').on('click', updateStageByClick);
function updateStageByClick() {
var id = $(this).parent().attr('class').substr(6);
var pid = $('form#data input[name=pid]').val();
var stage = $(this).val();
$.ajax({
type: "POST",
url: "/invite/stage",
data: {project: pid, user: id, stage: stage},
dataType: 'json',
success: update
});
return false;
}
<ul id="ul_stages" class="stage_<?= $profile['user_id'] ?>">
<li>SELECT STAGE:</li>
<li class="stage_unviewed stage" value="0">Unviewed</li>
<li class="stage_viewed stage" value="1">Viewed</li>
</ul>
尝试使用此:
$('form#data input[name="pid"]').val();
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