First off, this is for a homework assignment, so I'd appreciate help and guidance rather than just the answer in code.
The purpose of the code should be for a user to input a number and a width.
If the width is longer than the number, the number will be printed out with zeros in front of the number. For example 43 3
would give 043
.
If the width isn't longer just the number would be printed: 433 2
would be 433
.
I think I have to get the count of characters in the number and compare it to the count of characters in the width ( if-else
statement).
Then, if the number of characters in the number is more, print out the number. Else, print out the width.
I think I get the number of zeros by subtracting the length of the number from the length of the width. Then use that to set the number of zeros. Like I said this is homework and would rather learn than be given the answer.
If anyone can help, it'll be appreciated.
#include <iostream>;
#include <string>;
using namespace std;
string format(int number, int width) {
int count = 0;
if (number > width)// This if-else is incomplete
return ;
else
}
int main()
{
cout << "Enter a number: ";
string n;
cin >> n;
cout << "Enter the number's width: ";
string w;
cin >> w;
format(n, w);
}
no need to checking string or other things write these code C++ will do it for you automatically.
#include <conio.h>
#include <iostream>
using std::cout;
using std::cin;
#include <string>;
using std::string;
#include <iomanip>
using std::setw;
void format(int number, int width)
{
cout.fill('0');
cout << setw(width) << number;
}
int main()
{
cout << "Enter a number: ";
int n;
cin >> n;
cout << "Enter the number's width: ";
int w;
cin >> w;
format(n, w);
_getch();
return 0;
}
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