Why does this print 3 A's?

Question

It returns 3 A's but I don't see why that is?

Here is my code: for a certain int[] array = {3, 3, 2, 1, 3, 2, 1, 3, 3};

public static void returns(int[]array){
    for (int i = 0; i < array.length; i+= 2) {
        if (array[i] == 3) {
            System.out.print("A");
        }
     }
}

Answer 1

Because with an initial value of zero for i (and i+= 2 ) you are only testing the even indices, and of those only 0 4 and 8 are 3. You could use something like

System.out.printf("%d A ", i);

Instead of System.out.print("A"); to see for yourself.

I get

0 A 4 A 8 A

If you wanted to count the 3 (s), I'd prefer a for-each loop . Also, pass in the desired value. Something like

public static int count(int[] array, int value) {
    int count = 0;
    for (int i : array) {
        if (i == value) {
            count++;
        }
    }
    return count;
}